Submit the broadcast address of the following CIDR: 10.200.20.0/27

Submit the broadcast address of the following CIDR: 10.200.20.0/27

this only permit 32 usable ip telling us that -2 is 30 being 10.200.20.31 de answer

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how do you know its 32? in the module it says 64, how to know which to take when?

please how do you get the answer this is so confusing

well, In this problem, you can see the mask number is 24.But all mask number is 32, so, the mask numer is 32-27 = 5. 2^5 = 32, so the subnet ip address is 0~31.