What will be the file name of this after executing this code

I found this code
$fileName = date(‘ymd’) . ‘_’ . basename($_FILES[“uploadFile”][“name”]);
Let suppose my file name is payload.svg. So what will be the file name i tried as a 20211113_payload.svg ( istanbul time) but its not working.

The format would be 21113_filename.xxx or today it would be 211205__filename.xxx