Exercise Script
Code: bash
#!/bin/bash
# Count number of characters in a variable:
# echo $variable | wc -c
# Variable to encode
var="nef892na9s1p9asn2aJs71nIsm"
for counter in {1..40}
do
var=$(echo $var | base64)
done
Questions
Answer the question(s) below to complete this Section and earn cubes!
- Create an “If-Else” condition in the “For”-Loop of the “Exercise Script” that prints you the number of characters of the 35th generated value of the variable “var”. Submit the number as the answer.
My Answer
#!/bin/bash
# Count number of characters in a variable:
# echo $variable | wc -c
# Variable to encode
var="nef892na9s1p9asn2aJs71nIsm"
for counter in {1..40}
do
var=$(echo $var | base64);
# Check if the current iteration is the 35th
if [ $counter -eq 35 ]; then
echo "$(echo $var | wc -c)"
fi
done
[maximus@MaxBookPro Downloads]$ bash hi
800981
But it says that’s wrong? Why is this wrong?